Class 10 RD SHARMA Solutions Maths Chapter 10 - Trigonometric Ratios
Trigonometric Ratios Exercise Ex. 10.1
Solution 1 (i)
Solution 1 (ii)
Solution 1 (iii)
Solution 1 (iv)
Solution 1 (v)
Solution 1 (vi)
Solution 1 (vii)
Solution 1 (viii)
Solution 1 (ix)
Solution 1 (x)
Solution 1 (xi)
Solution 1 (xii)
Solution 2
In 
ABC by applying Pythagoras theorem
AC2 = AB2 + BC2
= (24)2 + (7)2
= 576 + 49
= 625
AC = 
= 25 cm 
Solution 3
Solution 4
Solution 5
Solution 6
Solution 7
Solution 8
Solution 9
Solution 10
Solution 11
Solution 12
Solution 13
Solution 14
Solution 15
Solution 16
Solution 17
Solution 18
Solution 19
Solution 20
Solution 21
Solution 22
Solution 23
Solution 24
Solution 26
Solution 27
Solution 28
Solution 29
Solution 30
Solution 31
Solution 32
Solution 33
Solution 34
Solution 35
Solution 36
Solution 25
Given: 
Trigonometric Ratios Exercise Ex. 10.2
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
Solution 6
Solution 7
Solution 8
Solution 9
Solution 10
Solution 11
Solution 12
Solution 13
Solution 14
Solution 15
Solution 16
Solution 17
Solution 18
Solution 19
Solution 20
Solution 21
Solution 22
Solution 23
Solution 24
Solution 25
Solution 26 (i)
Solution 26 (ii)
Solution 26 (iii)
Solution 26 (iv)
Solution 27 (i)
Solution 27 (ii)
Solution 27 (iii)
Solution 28 (i)
Solution 28 (ii)
Solution 29
Solution 30 (i)
Solution 31
Solution 32
Solution 33
Solution 34
Solution 35
Solution 36
Solution 37
Solution 38
Solution 39
Solution 40
Solution 30 (ii)
Given: tan(A + B) = 1 and 
Therefore,
A + B = 45o … (i)
A - B = 30o … (ii)
Adding the two equations, we get
Trigonometric Ratios Exercise Ex. 10.3
Solution 1
Solution 2 (i)
Solution 2 (ii)
Solution 2 (iii)
Solution 2 (iv)
Solution 2 (v)
Solution 2 (vi)
Solution 2 (vii)
Solution 2 (viii)
Solution 2 (ix)
Solution 2 (x)
Solution 2 (xi)
Solution 3
Solution 4
Solution 5
Solution 6(i)
Solution 6(ii)
Solution 7 (i)
Solution 7 (ii)
Solution 7 (iii)
Solution 7 (iv)
Solution 8 (i)
Solution 8 (ii)
Solution 8 (iii)
Solution 8 (iv)
Solution 8 (v)
Solution 9 (i)
Solution 9 (ii)
Solution 9 (iii)
Solution 9 (iv)
Solution 9 (v)
Solution 9 (vi)
Solution 9 (vii)
Solution 9 (viii)
Solution 9 (ix)
Solution 9 (x)
Solution 10
Solution 11 (ii)
Solution 12
Solution 13
Solution 14
Solution 15
Solution 16
Solution 17
Solution 6 (iii)
Given: ∠A = 90o
For a triangle ABC, ∠A + ∠B + ∠C = 90o
Solution 9 (xi)
Using the identities
Solution 11 (i)
For a triangle ABC, ∠A + ∠B + ∠C = 90o
Solution 18
Given: tan 2A = cot(A - 18o)
As tan x = cot(90o - x), we have
cot(90o - 2A) = cot(A - 18o)
90o - 2A = A - 18o
3A = 108o
Therefore, A = 36o.
Trigonometric Ratios Exercise 10.56
Solution 1
Solution 2
Solution 3
Solution 4
So, the correct option is (a).
Solution 5
Solution 6
Trigonometric Ratios Exercise 10.57
Solution 7
Solution 8
Solution 9
Solution 10
So, the correct option is (d).
Solution 11
So, the correct option is (c).
Solution 12
Solution 13
Solution 14
Solution 15
So, the correct option is (b).
Solution 16
So, the correct option is (a).
Solution 17
So, the correct option is (b).
Solution 18
So, the correct option is (d).
Trigonometric Ratios Exercise 10.58
Solution 19
Solution 20
So, the correct option is (b).
Solution 21
Solution 22
Solution 23
Solution 24
Solution 25
Solution 26
Solution 27
So, the correct option is (d).
Solution 28
So, the correct option is (a).
Solution 29
Solution 30
Solution 31
Solution 32
Trigonometric Ratios Exercise 10.59
Solution 33
So, the correct option is (c).
Solution 34
Solution 35
